:: : There are indeed two exponents because the indicial equation is quadratic, which is because the differential equation is second order.
2.
So, just to check, the two exponents at each regular singular point in the hypergeometric DE come from the fact that the indicial equation is a quadratic?
3.
The two solutions to the indicial equation are m = l + 1 and m =-l of which the former is taken as it yields the regular ( bounded, normalizable ) wave function.
4.
Its " exponents ", i . e . solutions of the indicial equation, for expansion around the singular point are and, corresponding to the two linearly independent solutions, and for expansion around the singular point they are and.
मोबाइल